20v^2+13vc-15c^2=0

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Solution for 20v^2+13vc-15c^2=0 equation:


Simplifying
20v2 + 13vc + -15c2 = 0

Reorder the terms:
13cv + -15c2 + 20v2 = 0

Solving
13cv + -15c2 + 20v2 = 0

Solving for variable 'c'.

Factor a trinomial.
(-5c + -4v)(3c + -5v) = 0

Subproblem 1

Set the factor '(-5c + -4v)' equal to zero and attempt to solve: Simplifying -5c + -4v = 0 Solving -5c + -4v = 0 Move all terms containing c to the left, all other terms to the right. Add '4v' to each side of the equation. -5c + -4v + 4v = 0 + 4v Combine like terms: -4v + 4v = 0 -5c + 0 = 0 + 4v -5c = 0 + 4v Remove the zero: -5c = 4v Divide each side by '-5'. c = -0.8v Simplifying c = -0.8v

Subproblem 2

Set the factor '(3c + -5v)' equal to zero and attempt to solve: Simplifying 3c + -5v = 0 Solving 3c + -5v = 0 Move all terms containing c to the left, all other terms to the right. Add '5v' to each side of the equation. 3c + -5v + 5v = 0 + 5v Combine like terms: -5v + 5v = 0 3c + 0 = 0 + 5v 3c = 0 + 5v Remove the zero: 3c = 5v Divide each side by '3'. c = 1.666666667v Simplifying c = 1.666666667v

Solution

c = {-0.8v, 1.666666667v}

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